Question

In n(a) =20, n(28) and n(a union b) =36 then n(a intersection b) =?
Plz ans with step by step explanation​

Answer 1

Answer:

the answer for this question is 12

Answer 2

n(a) =20, n(b)=28 , n(aub) =36 , n(anb) = ?

we know that

n(anb) =n(a) + n(b) - n(aub)

= 20+28 - 36 = 12

n(anb) = 12