In n {a} =20,n [B] =50, n [AUB] =60 and n [B']=20 . find n[AuB]and n [U]
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Answer:
n(A∩B) = 10
n(U) = 70
Step-by-step explanation:
n(A∩B) =n(A)+n(B)−n(A∪B)
n(A∩B) =20+50–60
n(A∩B) = 10
Also n(B′) =n(U)−n(B)
So,
20=n(U)−50
n(U) =50+20
n(U) =70
Kindly mark it as brainliest.
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