Chemistry, asked by hrishikaRathore, 3 months ago

In N3H, oxidation number of N atoms are :-
O -1,0,0
O -1/3,-1/3,-1/3
O -3, -3, -3
O -1,-1,0​

Answers

Answered by ysachin2839
1

Answer:

oxidation number of H atom = +1

oxidation number of N atom = x

sum of oxidation number of all atoms = 0

oxidation number of H + 3 × oxidation number of N = 0

1 + 3x = 0

x = - 1/3

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