In N3H, oxidation number of N atoms are :-
O -1,0,0
O -1/3,-1/3,-1/3
O -3, -3, -3
O -1,-1,0
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oxidation number of H atom = +1
oxidation number of N atom = x
sum of oxidation number of all atoms = 0
oxidation number of H + 3 × oxidation number of N = 0
1 + 3x = 0
x = - 1/3
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