Question

In NaCl lattice structure if one of the sodium ion is removed from corner, the formula of the resulting compound is .........

Answer 1

Answer:

cl^- remains after removal of Na from NaOH

Answer 2

The formula of resulting compound willl be Na₇Cl₈.

- In the structure of  NaCl, Na+ ions occupy the tetrahedral voids while the Cl −  ion makes up the FCC lattice .

- No of atoms at the corners = 1/2 ×6 = 3

And at the octahedral body diagonal = 1

- Total number of octahedral voids in FCC lattice = 4

- Thus, if the Na+ ion is removed from one of the corner then the total number of Na+ ion = 1/2 (6−1)+1=  7/2

And Number of Cl− ions = 4

- Ratio of Na+ to Cl- ions, Na+ : Cl- = 7/2 : 4

⇒ Na+ : Cl- = 7 : 8

- Therefore the formula will be Na₇Cl₈

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