"In NaCl there are apprximately 106 Schottky pairs per cm3 at room temperature. In 1 cm3 there are about 1022 ions. Thus, there is one Schottky defect per 1016 ions." Please explain how it is calculated that there is one Schottky defect per 101 6 ions .
Answers
Answered by
66
Hey dear,
● Explaination -
- For each cm^3, there are 10^6 Schottky pairs.
- For each cm^3, there are 10^22 ions.
Thus no of ions per Schottky pair are -
N = 10^22 / 10^6
N = 10^16 ions/schottky pair
Therefore, 10^16 ions are present per Schottky defect.
Thus proved. Hope this helps...
● Explaination -
- For each cm^3, there are 10^6 Schottky pairs.
- For each cm^3, there are 10^22 ions.
Thus no of ions per Schottky pair are -
N = 10^22 / 10^6
N = 10^16 ions/schottky pair
Therefore, 10^16 ions are present per Schottky defect.
Thus proved. Hope this helps...
Answered by
10
Given:
The no of Schottky pairs per cm³ = 10⁶
The no of ions per cm³ = 10²²
The no of ions per Schottky defect = 10¹⁶
To FInd:
The procedure to find the no of ions per Schottky defect calculated.
Solution:
- Here, 1 cm³ contains 10⁶ Schottky pairs and 10²² ions.
⇒ The no of ions per Schottky defect = The no of ions per cm³ / The no of Schottky pairs per cm³
⇒ The no of ions per Schottky defect = 10²²/10⁶
⇒ The no of ions per Schottky defect = 10¹⁶
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