In neutral spehre , 5*10"21 electron are present .if 10% electron are removed then calculate the charge on sphere
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Answered by
328
Given :-
In a neutral sphere, 5 × 10²¹ Electrons are present.
If 10 % of electrons are removed that means
= 10/100 ( 5 × 10²¹)
= 5 x 10²⁰ electron removed from sphere.
Here total charge on the sphere is increase in positive + charge, as equal to decrease in Negative - charge.
Hence the total charge removed = ( - 1.6 x 10⁻¹⁹ x 5 x 10²⁰ ) C.
= -1.6 x 5 x 10
= -80 C.
Therefore, If 10 % are removed then the total charge on the body is 80 C.
Now charge acting on the body is 80 C.
Hope it Helps.
In a neutral sphere, 5 × 10²¹ Electrons are present.
If 10 % of electrons are removed that means
= 10/100 ( 5 × 10²¹)
= 5 x 10²⁰ electron removed from sphere.
Here total charge on the sphere is increase in positive + charge, as equal to decrease in Negative - charge.
Hence the total charge removed = ( - 1.6 x 10⁻¹⁹ x 5 x 10²⁰ ) C.
= -1.6 x 5 x 10
= -80 C.
Therefore, If 10 % are removed then the total charge on the body is 80 C.
Now charge acting on the body is 80 C.
Hope it Helps.
Answered by
5
Answer:
charge acting on the body is 80C
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