Question

in non-reletiuistic regime if the momentum is increase by 100% the persentage increase in k.e is

Answer 1

A/q
Momentum =p=mv
If P is increased by 100% then
P1=100/100*P+P
P1=2P

Hence m1=m
V=2V
% change into k.e=1/2m(2v)^2-1/2mv^2 / 1/2mv^2 * 100
=(4-1)*100
=300%

Hope this will help you!!!