Question

in nth term of an AP is given by an =6-12n , then find the comman difference

Answer 1

Given

Tn= 6-12n

Now put n= 1
T1= 6-12(1)
= -6
n=2
T2= 6-12(2)
= -18
n= 3
T3= 6-12(3)
= -30
So series = -6,-18,-30+-----
So common diff= -18-(-6)
=-18+6
= -12 Ans

Answer 2

Hope it is correct.....