Question

In nuclear reactors, neutrons travel with

energies of 5 × 10-21 J. Find their speed

and wavelength.​

Answer 1

Speed of the neutron = 2.443 * 10^3 m/s while the wavelength is 1.620A.

Explanation:

Given that,

KE = 5 × 10-21 J

m = 1.675 * 10^-27 kg

h = 6.63 * 10^-34 J.s.

KE = 1/2 mv^2 = 5 * 10^-21 J

∵ v = $\sqrt{\frac{2KE}{m} }$= $\sqrt{\frac{(2) (5 * 10^{-21)} }{1.675 * 10^{-27} } }$

= 2.443 * 10^3 m/s

γ of neutron = h/mv

γ = (6.63 * 10^-34)/(1.675 * 10^-27) (2.443 * 10^3)

γ = 1.620 * 10^-10m

γ = 1.620A

Learn more: Calculate the wavelength

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