Question

In ∆NUT, if NU = 71 cm and UT = 92 cm. What is the length of side NT ​

Answer 1

Answer:

(H)^2 = (b)^2 + (p)^2

(H)^2 = (92)^2 + (71)^2

(H)^2 = 8464 + 5041

(H)^2 = 13505

H = ✓13505

H = 116.211015cm.