Question

In object of height 5cm is placed in front of concave mirror at a distance of 8cm for Focal length of mirror is 4cm. Find the height and nature of image​

Answer 1

Answer:

Given:-

1. Height of object h = 5cm
2. distance if object from mirror u=8cm
3. focal length of concave mirror f= 4cm
4. let 'v' be tha image distance

so, using mirror formula

1/f = 1/u +1/v

1/4 = 1/8 +1/v

so,

v = 8cm

now ,

-v/u = h'/h. [Here h'= height of image]

so

-8/8 = h'/5

h'= -5cm

hence we can conclude that

image will be of same size and will be erect