Question

In Ohm's experiment to measure resistance
different observation of unknown resistance are
4.12.2, 4.08 S2, 4.22 22 and 4.14 2. Find average
absolute error, relative error and percentage
error.

​

Answer 1

Answer:

Answer:

Absolute error = 0.02, 0.06, 0.08 and 0.00

Relative error =

Percentage errror = 9.67%

Explanation:

Absolute error: It is defined as difference between mean value and given individual value.

Given R₁=4.12, R₂=4.08, R₃=4.22,R₄=4.14

Mean value of all resistance=

=(R₁+R₂+R₃+R₄)/4=(4.12+4.08+4.22+4.14)/4

Absolute error,

ΔR₁= =4.14-4.12=0.02

ΔR₂= =4.14-4.08=0.06

ΔR₃= =4.14-4.22=0.08

ΔR₄= =4.14-4.14=0.00

Relative error:It is the ratio of absolute mean error and given individual mean value.

Δ=(0.02+0.06+0.08+0.00)/4=0.04

Relative error = Δ/=0.04/4.14=

Percentage error = when relative error is expressed in terms of percentage then percentage error is defined.

Percentage error = (Δ/)*100

=9.6