In Ohms law experiment the given resistance R is cut into two equal parts and parallel combination of this two parts are connected in between points X and Y in given circuit diagram. The net resistance between the points X and Y is
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Answer:
each new resistor will have a resistance of R/2
therefore when they are connected in parallel the new net resistance R¹ will be
1/R¹= 2/R+2/R
R¹ = R/4 is the final resistance between X and Y
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Explanation:
It becomes
1/R = 2/R + 2/R
= 4/R
R = R/4
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