Question

In one A.C. generator, brushes connected with slip rings become positive and negative alternatively at

the regular interval of 10 ms. Then angular frequency of this A.C. voltage would be ...... rad s-1

(A) 50 (B) 100 (C) 50 π (D) 100 π​

Answer 1

HELLO DEAR,

ANSWER:- (D) 100π

The angular frequency ω is given by

ω= 2π/T. The angular frequency in measured in radian per second.

So, given that 10 milli second it makes a regular alternate cycle.

Therefore it make a complete cycle in 5 milli second.

So, ω = 2π /T

ω = 2π/ (1/50)

ω = 2π × 50

ω = 100π.

I HOPE IT'S HELP YOU DEAR,

THANKS.

Answer 2

Answer: (D) 100π

Explanation:

The angular frequency ω is given by

ω= 2π/T. The angular frequency in measured in radian per second.

So, given that 10 milli second it makes a regular alternate cycle.

Therefore it make a complete cycle in 5 milli second.

$\omega ={{2\pi } \over T}$ω

$\omega = {2\pi \over (1/50)}$

$\omega = {2\pi\times 50}$

$\omega = {100\pi}$