Math, asked by saurav7780, 1 year ago

In one angle of the parallelogram is 16° less than three times the smallest angle, then the largest angle is?

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Answers

Answered by tigerraj01
7
Hope it will help you...
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Answered by BloomingBud
13
Let ABCD be the parallelogram.

Let the smallest angle (\angle{A} and \angle{C} ) be x degree. (small angles)

\angle{A} = \angle{C} and \angle{B} = \angle{D}
as opposite angles of parallelogram are equal.

Now,
According to the question,
the another angle = (3x-16)°

So,

\angle{A} + \angle{B} + \angle{C} + \angle{D} = 360°

=> x + (3x-16) + x + (3x-16) = 360°

=> 8x - 32 = 360°

=> 8x = 360 + 32

=> 8x = 392

=> x = 392 ÷ 8

=> x = 49

Hence,
smallest angle x° = 49°
and largest angle (3x-16)° = 3*49 - 16 = 131°

Therefore,
\angle{A} = \angle{C} = 49° each

\angle{B} = \angle{D} = 131° each
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