Question

In one district, the population increases by 4% in the first year and decreases by 5% in the second year. If the current population is 494000, what was the number of people two years ago?​

Answer 1

The population before two years was

450528

Step-by-step explanation:

494000*5/100=24700

494000-24700=469300

469300*4/100=18772

469300-18772=450528

Answer 2

Answer:

The number of people 2 years ago was 500000.

Step-by-step explanation:

Let the population be x

Therefore, 4% increase = x/25

After 1 year population = x+x/25 = 26x/25

2nd year population decreases by 5%

New population = (26x/25)-26x/25×5/100

= 26x/25-26x/500

Hence, 26x/25-26x/500 = 494000

520x-26x/500 = 494000

494x/500 = 494000

494x = 494000 × 500

x = 494000 × 500/494

= 1000 × 500 = 500000(ans)

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