Question

in one experiment 4g of h2o combines with 32g of O2 to give 36g of h2o. in other experiment 50g of H2 combines with 400g of O2 to give 450g of h20 .above two equation follow​

Answer 1

Answer:

Law of constant proportions

Answer 2

Answer:

The two equations follow​ the law of constant proportion.

Explanation:

The reaction of hydrogen with oxygen to produce water is as follows:-

$\mathrm{2H_2+O_2\rightarrow 2H_2O}$             (1)

Where,

H₂=hydrogen

O₂=oxygen

H₂O=water

From the question we have,

CASE I:-  4g of H₂ combines with 32g of O₂. The ratio of H₂:O₂ is 1:8.

CASE II:- 50g of  H₂ combines with 400g of O₂.The ratio of H₂:O₂ is 1:8.

So, from cases I and II we can analyze that the compounds follow the law of constant proportion. It is stated, " Chemical compounds are made up of components that are present in a fixed ratio by mass, according to the law of constant proportions. This indicates that the same components will always be present in the same proportion by mass in any pure sample of a compound, regardless of the source".

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