Question

In one litre of pure water, 44.4 g of calcium chloride is dissolved. The number of ions in
one mL of the resultant solution is:

(a) 7.23 × 10²³ (b) 7.23 × 10²⁰
(c) 4.82 × 10²³ (d) 4.82 × 10²⁰

Answer 1

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Question :-

In one litre of pure water, 44.4 g of calcium chloride is dissolved. The number of ions in one mL of the resultant solution is:

(a) 7.23 × 10²³     (b) 7.23 × 10²⁰

(c) 4.82 × 10²³     (d) 4.82 × 10²⁰

Answer :-

$\mathrm{Number\: of\: moles\: of\: CaCl_2 = \frac{Given\: mass}{Molecular\: Mass} }$

= $\frac{44.4}{111}$

= $\frac{\frac{444} {10} }{111} }$

= $\frac{444}{1110}$

= 0.4 mole

∵ 1 litre solution contain 0.4 mole of CaCl₂

$\mathrm{1mL\:= \frac{0.4}{1000} = 0.0004 }$

∴ 1 mL solution contain 0.0004 mole of  CaCl₂

∵ One CaCl₂ ionized into one Ca²⁺ and 2Cl⁻ ions.

So, the total number of ions = 3

∴ Total ions in 1 mL

= 3 × 0.0004 × 6.022 × 10²³

= 3 × $\frac{4}{10^3}$ × 6.022 × 10²³

= 3 × 4 × 6.022 × 10²⁰

= 7.23 × 10²⁰

Answer 2

Answer:

In one litre of pure water, 44.4 g of calcium chloride is dissolved. The number of ions in

one mL of the resultant solution is:

(a) 7.23 × 10²³ (b) 7.23 × 10²⁰

(c) 4.82 × 10²³ (d) 4.82 × 10²⁰

Explanation:

maybe option d) is the correct answer :)

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