Question

In one zero of a polynomial 3x2-8x+2k+1 is seven times the other find the value of k

Answer 1

Answer:

Let, one zero of polynomial be x then other be 7x

Sum of zeroes = x + 7x = 8x      ...(1)

Sum of zeroes = -b/a = 8/3       ...(2)

From eq.(1) and eq.(2)

8x = 8/3

x = 1/3

Product of zeroes = (x)(7x) = 7x^2    ...(3)

Product of zeroes = c/a = (2k + 1)/3   ...(4)

From eq.(3) and eq.(4)

7x^2 = (2k + 1)/3

7(1/3)(1/3) = (2k + 1)/3

2k + 1 = 7/3

k = 2/3