Question

in OPQ ,right -angled at P , OP= 7cm and OQ-PQ=1 cm (see fig 8.12). determine the value of sinQ and cosQ​

Answer 1

Answer:

Step-by-step explanation: in triangle OPQ, OP=7cm.

OQ-PQ=1cm

Let PQ=x

Therefore, OQ=1+x

By Pythagoras theorem

(OQ)^2=(OP)^2+(PQ)^2

(1+x)^2=7^2+x^2

2x=49-1

2x=48

X=24

PQ=24

Therefore , OQ= 25

SinQ=p/h= 7/25

CosQ= b/h= 24/25