Question

In optical fibre the refractive index of the core material is 1.6 and the refractive index of the cladding material is 1.3, then calculate the vertex angle of the acceptance cone

Answer 1

Explanation:

Sol: Let the refractive index of core, n1 = 1.48

and the refractive index of cladding , n2 = 1.45

Numerical aperture (NA) images

images

Answer 2

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◆ Answer -

c = 54.34°

α = 68.86°

● Explanation -

Critical angle is calculated as -

sinc = n2/n1

sinc = 1.3/1.6

sinc = 0.8125

c = arcsin(0.8125)

c = 54.34°

Angle of acceptance ia given by -

sinα = √(n1^2-n2^2) / n0

sinα = √(1.6^2-1.3^2) / 1

sinα = √(2.56-1.69)

sinα = √(0.87)

sinα = 0.9327

α = arcsin(0.9327)

α = 68.86°

HOPE SO IT WILL HELP....