Question

In order to carry out the decomposition reaction of water, a student passes electric current from a battery through water containing a few drops of dilute sulphuric acid. In this process, two volume of gas X are collected in a test-tube inverted over cathode (negative electrode) whereas one volume of gas Y is collected in the test-tube inverted over anode (positive electrode).
(a) Why do we add a few drops of dilute sulphuric acid to water before passing electric current?
(b) Name the gas X.
(c) Name the gas Y.
​(d) What does this decomposition reaction tell us about the composition of water?

Answer 1

(a) We add a few drops of dilute sulphuric acid to water before passing electric current to increases the water decomposition rate.

(b)The gas X is hydrogen

(c) The Y gas is oxygen

(d) Water gets splitted into two hydrogen ions and one oxygen ion

Explanation:

(a) Water decomposition is a very moderate process and the addition of dilute sulphuric acid increases the water decomposition rate.

$2H_{2} O -> H + 2H_{2} + O_{2}$

(b) The gas X is hydrogen, which gathers in the cathode because the positively charged hydrogen ions are transferred to the negatively charged cathode electrode.

(c) The Y gas is oxygen that gathers in the anode because the negative oxygen ions are transferred to the positive charging electrode.

(d) When transmitting electricity in water, this water is divided into two hydrogen ions and one oxygen ion.

You can get all the answers of Chapter 8 in the link below:    

https://brainly.in/question/15022359

   

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