Question

In order to conduct an experiment, the temperature of a liquid was lowered at the rate of 2°C every hour. If the initial temperature of the liquid was 5°C, what was its temperature after 4 hours? who will answer i will mark brainlest

Answer 1

Answer:

-3°C

Step-by-step explanation:

2°C every hour times 4 hours

(2x4=8)

8-5=-3

add your unit (°C)

and then you get -3°C

hope this helps!

Answer 2

Given:

• Initial Temperature = 5°c
• After every hour temperature is lowered at the rate of = 2°c

Find:

• What will be the temperature after 4hrs

Solution:

$\sf \mapsto In \: 1hrs \: temp. \: is \: lowered \: by \: 2^{\circ}c$

$\sf Therefore, In \: 4hrs \: temp. \: is \: lowered \: by$

$\sf = 2 \times 4 \\ \sf = 8^{\circ} c$

$\sf \therefore in \: 4hrs \: temp. \: is \: lowered \: by \: {8}^{\circ}c$

Now,

$\sf \mapsto Initial \: temp. = 2^{\circ}c$

$\sf So, temp. \: after \: 4hrs$

$\sf = 5^{\circ} c -8^{\circ} c \\ \sf = - 3^{\circ} c$

$\sf \therefore after \: 4hrs \: temp. \: will \: be \: { -3}^{\circ}c$

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Temperature of water after 4hrs = -3°c