Question

In order to conduct Sports Day activities in your School, lines have been drawn with chalk powder at a distance of 1 m each, in a rectangular shaped ground ABCD, 100 flowerpots have been placed at a distance of 1 m from each other along AD, as shown in given figure below. Niharika runs 1/4 th the distance AD on the 2nd line and posts a green flag. Preet runs 1/5 th distance AD on the eighth line and posts a red flag.​

Answer 1

Step-by-step explanation:

This is the answer

Answer 2

Given:

100 flowerpots

Niharika runs 1/4th the distance AD on the 2nd line

Niharika x- ordinate =2

Niharika y- ordinate =1/4×100 =25

So position of red flag is (2, 25)

Preet runs 1/5 th distance AD on the eighth line

preet x- ordinate = 8

preet y - ordinate = 1/5×100 =20

So positon of red flag is (8, 20)

A(2,25) and  B(8,20)

$AB=\sqrt{(x2-x1)^{2}+(y2-y1)^{2} }$

$AB=\sqrt{(20-25)^{2}+(8-2)^{2} }$

$AB=\sqrt{(-5)^{2}+6^{2} }$

$AB=\sqrt{25+36}$

$AB=\sqrt{61}$

Distance between both flags is  √61

Rashmi has to place her flag at the midpoint of AB.

MIdpoint of AB = $\frac{2+8}{2},\frac{25+20}{2}$

= (5,22.5)

Hence answer are as follows:

(1) option "a" .

position of green flag is (2, 25)

(2) Option "c"

Potion of red flag is (8,20)

(3) Option "b"

Distance between both the flags is √61

(4) The answer is  (5,22.5)