Question

in order to move a charge of 3C between two points on a conducting wire 12J of work is done . how much increase or decrease in the voltage will increase the work done on the some amount of charge to 36J​

Answer 1

Answer:

here 4 volt is required initially

Explanation:

now keep charge constant ie 3 coulomb and then find the new potential difference by taking energy as 36 joule which is 12 volt

now increase in voltage is 12V-4V=8 volt

Answer 2

Given,

Charge of particle = 3 C

Initially, the work done on the charge= 12 J

Finally, the work done on the charge = 36 J

To find,

The increase or decrease in voltage if work is done on the same charge increases to 36 J.

Solution,

This question can easily be solved since we know,

E = QV

where E = work done

Q = charge

and V = voltage

initially,

E = 12 J

⇒ 12 = 3 × V$_i$

⇒ V$_i$ = 4 V

Finally,

E = 36 J

⇒ 36 = 3 × V$_f$

⇒ V$_f$ = 12 V

now the change in voltage = V$_f$ - V$_i$ = 8 V

∴ The increase in the voltage required to increase the work done on the same charge (3C) to 36 J, is 8 V.