In order to obtain a magnification of,-2.0 with a concave mirror of focal length 12cm,the object will have to be placed at a distance
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Answer:
Given,
Object distance, u=12cm
magnification, m=4
We know,
m=
u
−v
−4=
−12
−v
v=−48cm
from mirror formula
f
1
=
v
1
+
u
1
=−
48
1
−
12
1
=−[
12×48
12+48
]
=−[
48
5
]
f=−9.6cm
Radius of curvature, R=2f
=−2×9.6
R=−19.2cm
Explanation:
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