In order to raise a mass m a man ties it to a rope and passes the rope over a frictionless pulley. He climbs the
rope with an acceleration 3g/2 relative to the rope. If the mass of the man is m/2 and the mass of the rope is
negligible, the tension in the rope is
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Answer:
Explanation:
let acceleration of rope is a
then acceleration of man = a+ 3g/2
applying equation for mass m
mg-t = ma
applying equation for m/2 mass
t-mg/2 = m/2(a+ 3g/2)
mg/2 = 3ma/2 + 3mg/4
g = 3a + 3g/2
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