Physics, asked by karan5058, 1 year ago

In order to raise a mass m a man ties it to a rope and passes the rope over a frictionless pulley. He climbs the
rope with an acceleration 3g/2 relative to the rope. If the mass of the man is m/2 and the mass of the rope is
negligible, the tension in the rope is​

Answers

Answered by nagathegenius
5

Answer:

Explanation:

let acceleration of rope is a

then acceleration of man = a+ 3g/2

applying equation for mass m

mg-t = ma

applying equation for m/2 mass

t-mg/2 = m/2(a+ 3g/2)

mg/2 = 3ma/2 + 3mg/4

g = 3a + 3g/2

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