Question

In order to raise a mass of 100kg, a man of mass 60kg fastens a rope to it and passes the rope over a smooth pulley. He climbs the rope with acceleration 5g/4 relative to the rope. The tension in the rope is​

Answer 1

Answer:

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Explanation:

In order to raise a mass of 100 kg, a man of mass 60 kg fastens a rope to it and passes the rope over a smooth pulley. He climbs the rope with acceleration 5g/4 relative to the rope.The tension in the rope is (take g=10ms²).

Let a

r

be the acceleration of man relative to a and a

m

be the acceleration of man.

T−mg=ma

m

T−Mg=Ma

Now a

m

=a

r

−a

⇒g(M−m)=Ma−ma

r

+m

a

⇒a=

(M+m)

[g(M−m)+ma

r

]

Given M=100kgm=60kg a

r

=

4

5

g

⇒a=

160

[(−10)×40+750]

a=

16

35

T=m(g+a)=

4

4875

N

solution

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