In order to verify the law of conservation of mass, a student mixed 6.3 g of sodium carbonate and 15.0 g of ethanoic acid in a conical flask. After experiment, he weighed the flask again. The weight of the residue in the flask was only 18.0 g. He approached the teacher who guided him to carry the experiment in a closed flask with a cork. There was no difference in weight of the flask before and after the experiment. a. What was the mistake committed by the student ? b. Why did not the two weights match earlier ? C. How did the teacher help him ? d. What lesson was learnt by the student?
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>>If 6.3 g of NaHCO3 are added to 15.0 g o
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If 6.3g of NaHCO3 are added to 15.0g of CH3COOH solution, the residue is found to weigh 18.0g. What is the mass of CO2 released in the reaction?
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The chemical reaction will be:
NaHCO3+CH3COOH→CH3COONa+H2O+CO2
molarmass:NaHCO3=84CH3COOH=60CH3COONa=82CO2=4484gNaHCO3+60gCH3COOH→82gCH3COONa+44gCO2
Moles of NaHCO3=84
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