Question

in organic compound c=40% and h =6.66 % its vapor density is 90 . calculate its empirical and molecular formul






please answer its urgent please​

Answer 1

Answer:

Empirical Formula : CH₂

Molecular Formula : C₁₂H₂₄

Explanation:

Atomic mass of carbon = 12

No.of carbon atoms = 40/12 = 3.33/3.33 = 1

Atomic mass of hydrogen = 1

No. of hydrogen atoms = 6.66/1 = 6.66/3.33 = 2

(No. of atoms must be divided by smallest value)

Therefore, empirical formula = CH₂

n = V.D * 2/ molecular mass

  = 90*2/15

n = 12

Molecular formula = (CH₂)ⁿ

                              = C₁₂H₂₄