Question

in our class of 50 students 28 of that for NCC and 28 of that for NSSand 10 of that for both and NSS one of the students selected at random find the probability that the student of that for NCC but not NSS distance of that for NSS but not NCC
this is not that for exactly one of them ​

Answer 1

14:25

Step-by-step explanation:

propability of getting ncc not nss is 28÷50

=14÷25

Answer 2

Step-by-step explanation:

Given :  In a class of 50 students, 28 opted for NCC, 30 opted for NSS and 18 opted for NCC and NSS

To find : the probabilities if one students is selected at random

Solution:

Total Students  = 50

NCC  = 28

NSS  = 30

Opted for Both = NCC ∩ NSS = 18

opted for None = ?

50 = 28 + 30  - 18 + none

=> none = 10

10 opted for none

Opted for NCC but not NSS = NCC - (NCC ∩ NSS)

= 28 - 18

= 10

Probability = 10/50  = 1/5

opted for NSS but not NCC = NSS - (NCC ∩ NSS)

= 30 - 18

= 12

Probability = 12/50  = 6/25

student opted for exactly one of them = 10 + 12 = 22

Probability  = 22/50

= 11/25

1/5 Opted for NCC but not NSS  

6/25 opted for NSS but not NCC

11/25 opted for exactly one of them