in p(x) = (x -a) q(x) + r, p(x) =r when x =_______
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Answer:
x=a
Step-by-step explanation:
given, p(x) = (x -a) q(x) + r
if p(x) = r
=> x -a =0 (or) q(x) = 0
=> x = a (or) q(x)=0
here, the answer is about the value of x and not about q(x)
so we take x=a as the answer.
when x=a, we arrive at p(x) = r
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