In page no117 of NCERT Chemistry book, it is given that the shape (a) is the most stable for CF3. However, isn't lone-pair lone-pair repulsion present in shape (a)? So, it should be the least stable one right? Since lone pair lone-pair repulsion is greater than lone-pair bond pair repulsion??
Please help me with my doubt...
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lone pair repulsion is strongest because they are free moving electrons so they will move as far away from each other as possible. bonding pair-lone pair repulsion is not as strong because bonding pair does not moves freely therefore they will not repel. Lone pair repulsion affects the shape molecule. lone pair at equatorial position is stable.
according to VSEPR theory, t shaped geometry results when 3 ligands and two lone pairs of electrons are bonded to the central atom has three ligands. that three co-ordinated compounds adopt trigonal planar . example of t shaped molecules are the halogen trifluoride ,like CIF3 etc...
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