in parallelogram ABCD 4 angle a=5 angle c then find angle c
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Answer:
Let ABCD be a parallelogram in which ∠A=65
∘
.
Since AD∥BC we can treat AB as a transversal. So,
∠A+∠B=180
∘
65
∘
+∠B=180
∘
∠B=180
∘
−65
∘
∠B=115
∘
Since the opposite angles of a parallelogram are equal, we have
∠C=∠A=65
∘
and ∠D=∠B=115
∘
Hence, ∠B=115
∘
,∠C=65
∘
and ∠D=115
∘
solution
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