Math, asked by neerajsachdeva511, 3 months ago

In parallelogram ABCD /_A=60^(0) find the remaining angles of the parallelogram.Also if the diagonals intersect at point O find OA OB OC and OD given AC=6cm BD=10cm.​

Answers

Answered by farhaanaarif84
2

Answer:

ABCD is a parallelogram whose diagonals intersect each other at O with 90°.

so it's a rhombus as diagonals of rhombus interest each other at right angles.

diagonal1 (AC) = 6cm

diagonal 2(BD) = 8cm

OD = OB = 3cm each

OA = OC = 4cm each

Let, us take triangle AOB

it is a right angled triangle

=> (OA)² + (OB)² = (AB)²

=> (4)² + (3)² = (AB)²

=> 16 + 9 = (AB)²

=> 25 = (AB)²

=> = AB

=> 5 = AB

So, AB = 5cm

AB = BC = CD = AD (all sides of rhombus are equal)

Each side of the parallelogram ABCD is 5cm.

Answered by mmuralikrishna383
0

answe:Ac=6 cm plz add with Bc u can get answer

dont forget to like

Similar questions