Question

In parallelogram ABCD, ∠A - ∠B = 40°. Complete the following activity to find the measure of ∠A
AD | BC and AB is the transversal
∠A+B= (Interior angles) ... (1) .
∠A - ∠B= (Given) ... (2)
Adding (1) and (2), we get
2∠A= ∠A= ​

Answer 1

Answer:

Angles of parallelogram in order are 110°, 70°, 110°, 70°.

Step-by-step explanation:

Hi,

Given a parallelogram ABCD in which

ZB ZA = 40°

-(1).

But, we know adjacent angles in a parallelogram are supplementary

Hence, 2 B + ZA = 180°-------(2)

From (1) and (2), we get

< B = 110° and <A = 70°.

Also, we know that opposite angles in a parallelogram are equal.

Hence, C = < A = 70° and

ZD=B= 110°

Thus the angles of parallelogram in order are 110°, 70°, 110°, 70°.

Hope, it helps!

Answer 2

Answer:

110

Step-by-step explanation:

Given <A- <B =40° ... i

<A+<B=180° ... ii (interior angle)

On adding equation i & ii we get

2<A=220

So, <A=220/2=110°