Question

in parallelogram ABCD,AB=10 cm. The altitudes corresponding to sides AB and AD are 7cm and 8cm respectively.Find AD

Answer 1

Using the formula of area of parallelogram,
$\frac{1}{2} \times ab \times altitude1 = \frac{1}{2} \times ad \times altitude2 \\ab \times altitude1 = ad \times altitude2 \\ 10 \times 7 = ad \times 8 \\ ad = \frac{70}{8} = \frac{35}{4} = 8.75$

Answer 2

Thank you for asking this question. Here is your answer:

AB = 10 cm

DE = 7 cm

BF = 8 cm

Now the area of parallelogram  = base x corresponding height

AD x BF = AB x DE

AD x 7 =  10 x 8

AD = (10*7) / 8

AD = 70/8

= 8.7 cm

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