Question

in parallelogram ABCD AB = 5x -4, CD =3x+6, AD = 2y+3 , BC= 3y-5 find the length of each side of the parallelogram​

Answer 1

Step-by-step explanation:

In parallelogram opp.sides are equal

so AB=CD

5X-4=3X+6

5X-3X=6+4

2X=10

X=10/2

X=5

similarly AD=BC

2Y+3=3y-5

3+5=3Y-2Y

Y=8

so,length of AB=5(5)-4=25-4=21

CD=3(5)+6=15+6=21

AD=2(8)+3=16+3=19

BC=3(8)-5=24-5=19

Answer 2

Answer:

Step-by-step explanation:In parallelogram opp.sides are equal

so AB=CD

5X-4=3X+6

5X-3X=6+4

2X=10

X=10/2

X=5

similarly AD=BC

2Y+3=3y-5

3+5=3Y-2Y

Y=8

so,length of AB=5(5)-4=25-4=21

CD=3(5)+6=15+6=21

AD=2(8)+3=16+3=19

BC=3(8)-5=24-5=19