In parallelogram ABCD, AB = 9 cm, BC = 10 cm and AC = 17 cm, then find its area.
Answers
Answered by
0
Answer:
We have to put the formula of base x height.
Step-by-step explanation:
But in the question there is no perpendicular height. So we can't give the answer.
Answered by
1
Answer:
Area of Parallelogram ABCD=2×ar△ABC
ar△ABC=
s(s−a)(s−b)(s−c)
s=
2
a+b+c
=
2
16+10+12
=19cm
ar△ABC=
19(19−16)×(19−10)(19−12)
=
169×3×9×7
=59.9cm
2
∴ area of parallelogram ABCD=2×59.9=119.8cm
2
Now, area of parallelogram ABCD=base X height
119.8=10×h⇒h=11.98cm
∴ Distance between the shortest sides is 11.98cm
Step-by-step explanation:
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