Math, asked by thakerdhyey, 23 hours ago

In parallelogram ABCD, AB = 9 cm, BC = 10 cm and AC = 17 cm, then find its area.​

Answers

Answered by rajeshkumar940092
0

Answer:

We have to put the formula of base x height.

Step-by-step explanation:

But in the question there is no perpendicular height. So we can't give the answer.

Answered by ananyanaskar28
1

Answer:

Area of Parallelogram ABCD=2×ar△ABC

ar△ABC=  

s(s−a)(s−b)(s−c)

 

s=  

2

a+b+c

=  

2

16+10+12

=19cm

ar△ABC=  

19(19−16)×(19−10)(19−12)

 

=  

169×3×9×7

 

=59.9cm  

2

 

∴ area of parallelogram ABCD=2×59.9=119.8cm  

2

 

Now, area of parallelogram ABCD=base X height

119.8=10×h⇒h=11.98cm

∴ Distance between the shortest sides is 11.98cm

Step-by-step explanation:

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