In parallelogram ABCD, AC is diagonal and the area of triangle ABC is 30 cm square . Then, the area of parallelogram ABCD is
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given, area of ABC=30cm^2
in the figure, the diagonal AC divides the parallelogram into two congruent triangles.
therefore, ADC=ABC
AREA OF PARALLELOGRAM ABCD =
AREA OF ADC + AREA OFABC
=2(AREA OF ABC)
=2*30=60cm^2
in the figure, the diagonal AC divides the parallelogram into two congruent triangles.
therefore, ADC=ABC
AREA OF PARALLELOGRAM ABCD =
AREA OF ADC + AREA OFABC
=2(AREA OF ABC)
=2*30=60cm^2
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Answer:
60 cm^2
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