Math, asked by riowithgaming, 1 day ago

In parallelogram ABCD, AC is the angle bisector of angle BAD. Prove that ABCD is a rhombus.​

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Answered by ac8804
0

Answer:

theoretically Rhombus is a "Quadrilateral in which all four sides are equal to both pairs of opposite sides are parallel is called rhombus". as given: AC diagonal bisects ∠A in ABC D∣∣ & ∠C AD = ∠C AB

Step-by-step explanation:

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