in parallelogram ABCD angle A=(4x+5) and angle C=(3x+10). find angle A and B
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Answered by
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Angle A = Angle C.......1)Opposite angles of a parallelogram
(4x+5)=(3x+10).........given
4x-3x=10-5
:.x=5
Angle A=(4*5+5)
=25°
Angle C=25°......from 1)
(4x+5)=(3x+10).........given
4x-3x=10-5
:.x=5
Angle A=(4*5+5)
=25°
Angle C=25°......from 1)
mauryasaurabh47:
sir ek galti ho gayi waha angle A=(4x-5) hoga answer me
nahi bro batabar hain
varna answer galat aaega
kya
if the condition is - 5 then the ans is wrong so it is correct
Answered by
1
heyaa !!!!
As it is parallelogram...so opposite angles are equal..
Angle A = Angle C
4x + 5 = 3x + 10
4x - 3x = 10 - 5
x = 5
so.. Angle A = 4 × 5 + 5
= 25
and angle B = 155 { Sum of all sides of //gram is 360)
hope it helps you✌️
#APS☺️☺️
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