in parallelogram ABCD,angle A = angle B+50°, then find
of each angle of the quadrilateral ABCD
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Answer:
in a parallelogram sum of angles is 360
opposite angles are equal
adjacent angles sum is 180
since angle A and angle B are adjacent angles their sum is 180
given angle A=angleB +50°
so
A+B=180
B+50+B=180
2B=180-50
2B=130
B=65
A=50+65
A=115
therefore, the angles are
115,65,115,65
hope it helps you☺️
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