Question

in parallelogram ABCD angle A is equal to Angle B + 50 degree find all the angles of quadrilateral ABCD​

Answer 1

In the parallelogram the opposite angles are equal and the corresponding angles are complementary.

Hence Angle A + Angle B = 180 degree

Now, angle A = angle B + 50

Therefore, angle A +( angle A + 50) = 180

2( angle A) = 130

Angle A = 65 degree

Angle A = angle B + 50

65= angle B + 50

Hence Angle B = 15 degree

Angle C = 65 degree ( opposite angles are equal)

Angle D = 15 degree ( opposite angles are equal)

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Answer 2

In parallelogram adjacent angles are supplementary and opposite angles are congruent.

let angle B be x degree

then angle A be x+50 degree

angle A and angle B are supplementary angles

therefore

x+x+50=180

2x+50=180

2x=130

x= 65

angle A is 115 degree

angle B is 65 degree

angle A= angle C. ............opposite angles

therefore angle C =115 degree

angle B= angle D ...........opposite angles

therefore angle D= 65 degree

ANS

angle A=115 degree

angle B= 65 degree

angle C= 115 degree

angle D= 65 degree