in parallelogram ABCD angle A is equals to angle b + 50 find all the angle of quadrilateral ABCD
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hello mate!
angle A= angle B + 50°
now,
let angle B be x and angle A be x+50°
we know, as angle A and Angle B are adjacent angles, their sum would be
180°....(1)
therefore,
x+ x+50°=180°
2x= 130°
x= 65°....(2)
now angle A would be= 50+ 65= 115°....(3)
here,
angle A is equal to angle C
and angle angle B is equal to angle D...... ( opposite angles)
therefore,
angle C= 115°
angle D= 65°
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