Question

in parallelogram abcd, angle b - angle a = 40 degree. find all the angles of a parallelogram abcd.

Answer 1

Answer:

Angles of parallelogram in order are 110°, 70°, 110°, 70°.

Step-by-step explanation:

Hi,

Given a parallelogram ABCD in which

∠ B - ∠ A = 40° --------------------(1).

But, we know adjacent angles in a parallelogram are supplementary

Hence, ∠ B + ∠ A = 180° -------(2)

From (1) and (2) , we get

∠ B = 110° and  ∠ A = 70°.

Also, we know that opposite angles in a parallelogram are equal.

Hence, ∠ C = ∠ A = 70° and

∠ D = ∠ B = 110°

Thus the angles of parallelogram in order are 110°, 70°, 110°, 70°.

Hope, it helps !

Answer 2

Answer:

So another angles of parallelogram are ∠A = 70° , ∠B = 110° , ∠C = 70° , ∠D = 110° .

Step-by-step explanation:

Hey Mate,

We known that the sum of adjacent angles is 180°

So,

∠A + ∠B = 180° ..........(1)

∠B - ∠A = 40° .............(2)

Equation (1) - (2)

(∠A + ∠B) - (∠B - ∠A) = 180° - 40°

2∠A = 140°

∠A = 70°

Put the value of ∠A in equation (2)

∠B - ∠A = 40°

∠B - 70° = 40°

∠B = 40° + 70°

∠B = 110°

So another angles of parallelogram are ∠A = 70° , ∠B = 110° , ∠C = 70° , ∠D = 110° .