In parallelogram abcd angle b minus angle a is 40 find all the angles of abcd
Answers
Answered by
2
Pic have the solution
Attachments:
Answered by
3
let angle b=x
angle a=x +40
x+x +40=180 (sum of adjacent angles of parallelogram is 180)
2x+40=180
2x=180-40
2x=140
x=140÷2
x=70
angle b =70
angle a =70 +40=110
angle b =angle c
angle a=angle d
angle a=x +40
x+x +40=180 (sum of adjacent angles of parallelogram is 180)
2x+40=180
2x=180-40
2x=140
x=140÷2
x=70
angle b =70
angle a =70 +40=110
angle b =angle c
angle a=angle d
Similar questions