in parallelogram ABCD, angleA=(4x-5) and(3x+10). find angleA and angleB
Answers
Answered by
31
Answer:
<A = 55°
<B = 125°
Step-by-step explanation:
<A = (4x-5) and (3x+10)
so,
<A = <C (in parallelogram opposite angles are equal)
(4x-5) = (3x+10)
4x-3x = 10+5
x = 15
<A = 4x-5
= 4(15)-5
= 60-5
= 55°
<B = <A+<B = 180° (in parallelogram sum of adjacent angles are 180°)
<B = 55° + <B = 180°
<B = 180° - 55° = 125°
<A = 55°
<B = 125°
Answered by
22
Correction :-
- In a parallelogram ABCD, ∠A = (4x - 5)° and ∠C = (3x + 10)°. Find ∠A and ∠B.
Answer :-
- ∠A = 55°
- ∠B = 125°
Solution :-
Here,
- ∠A = (4x - 5)
- ∠C = (3x + 10)
∠A = ∠C [ opposite angles of the parallelogram ]
→ (4x - 5) = (3x + 10)
→ 4x - 5 = 3x + 10
→ 4x - 3x = 10 + 5
→ x = 15
Now,
- ∠A = 4(15) - 5 = 60 - 5 = 55°
We've to find ∠B
According to question :-
∠A + ∠B = 180° [ adjacent angles of a parallelogram ]
55° + ∠B = 180°
∠B = 180° - 55°
∠B = 125°
Hence, the values of ∠A and ∠B are 55° and 125° respectively.
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