Question

In parallelogram ABCD, AX is bisector of angleA
and CY is the bisector of angleC. Prove that AXCY
is a parallelogram.
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Answer 1

Answer:

Answer:

Step-by-step explanation:

Given,

ABCD is a Parallelogram

AX is the bisector of ∠A

CY is the bisector of ∠C

To Prove

AX ║ CY

Proof

ABCD is a parallelogram

∴ ∠A = ∠C(Opp. angles of a paralleogram are equal)

∠A = ∠C (Halves of equals are equal)

∴ ∠1 = ∠2

(AX and CY bisects A and C)

AB ║CD and CY is the transversal (Parallel lines of a parallelogram)

∴ ∠2 = ∠3

But ∠1 = ∠2

⇒ ∠1 = ∠3

∴ AX ║ CY

(Corresponding angles 1 and 3 are equal, therfore the lines are parallel)

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Answer 2

$\huge\underline\pink{ANSWER:}$

Given,

ABCD is a Parallelogram

AX is the bisector of ZA

CY is the bisector of C

To Prove :

AX ll CY

Proof :

ABCD is a parallelogram

:. ZA = ZC(Opp. angles of a paralleogram are equal)

ZA = ZC (Halves of equals are equal)

:. / 1 = / 2

(AX and CY bisects A and C)

AB CD and CY is the transversal (Parallel lines of a parallelogram)

:. / 2 = / 3

But / 1 = / 2

=> / 1 = / 3

:. AX || CY

(Corresponding angles 1 and 3 are equal, therfore the lines are parallel)

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