Math, asked by Rits96, 1 year ago

In parallelogram ABCD, bisector of angle C meet AD at E . CE and BA produced meet at F, Prove that
BC = BF

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Answers

Answered by aseedaameer19313

7

FCB=CDE

AD||BC

FAE=ACF

so,BC=BF......BY SSS CONGRUENCE RULE

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